2(p^2+4)=7p^2+1

Solution for 2(p^2+4)=7p^2+1 equation:

Simplifying
2(p2 + 4) = 7p2 + 1

Reorder the terms:
2(4 + p2) = 7p2 + 1
(4 * 2 + p2 * 2) = 7p2 + 1
(8 + 2p2) = 7p2 + 1

Reorder the terms:
8 + 2p2 = 1 + 7p2

Solving
8 + 2p2 = 1 + 7p2

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-7p2' to each side of the equation.
8 + 2p2 + -7p2 = 1 + 7p2 + -7p2

Combine like terms: 2p2 + -7p2 = -5p2
8 + -5p2 = 1 + 7p2 + -7p2

Combine like terms: 7p2 + -7p2 = 0
8 + -5p2 = 1 + 0
8 + -5p2 = 1

Add '-8' to each side of the equation.
8 + -8 + -5p2 = 1 + -8

Combine like terms: 8 + -8 = 0
0 + -5p2 = 1 + -8
-5p2 = 1 + -8

Combine like terms: 1 + -8 = -7
-5p2 = -7

Divide each side by '-5'.
p2 = 1.4

Simplifying
p2 = 1.4

Take the square root of each side:
p = {-1.183215957, 1.183215957}